5x^2-8x-4=3x-4

Solution for 5x^2-8x-4=3x-4 equation:

5x^2-8x-4=3x-4

We move all terms to the left:

5x^2-8x-4-(3x-4)=0

We get rid of parentheses

5x^2-8x-3x+4-4=0

We add all the numbers together, and all the variables

5x^2-11x=0

a = 5; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·5·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*5}=\frac{0}{10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*5}=\frac{22}{10}
=2+1/5
$